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  9. Q99

IBPS PO 2020 · Question 99 of 99

In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer: I. x^2 - 20x + 91 = 0 II. y^2 - 34y + 273 = 0

Quadratic Equations

  1. Ax > y
  2. Bx >= y
  3. Cx < y
  4. Dx <= yCorrect
  5. Ex = y or the relation cannot be determined

Answer: D. x <= y

Explanation

Equation I: x^2 - 20x + 91 = 0 => x^2 - 13x - 7x + 91 = 0 => x(x - 13) - 7(x - 13) = 0 => (x - 7)(x - 13) = 0 => x = 7 or x = 13. Equation II: y^2 - 34y + 273 = 0 => y^2 - 21y - 13y + 273 = 0 => y(y - 21) - 13(y - 21) = 0 => (y - 21)(y - 13) = 0 => y = 21 or y = 13. Value of x / Value of y / Relation: 7, 13 -> x x x = y; 13, 21 -> x < y. Therefore, x <= y.

Source: IBPS PO 10-Oct-2020 Prelims Memory Based Paper Shift 1 (Prepp) · memory-based

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