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  9. Q13

IBPS PO 2011 · Question 13 of 237

Directions: Study the following information to answer the given questions. A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule. The following is an illustration of input and rearrangement. (All the numbers are two-digit numbers.) Input: sine 88 71 cos theta 14 56 gamma delta 26 Step I. cos sine 71 theta 14 56 gamma delta 26 88 Step II. delta cos sine theta 14 56 gamma 26 88 71 Step III. gamma delta cos sine theta 14 26 88 71 56 Step IV. sine gamma delta cos theta 14 88 71 56 26 StepV. theta sine gamma delta cos 88 71 56 26 14 Step V is the last step of the rearrangement. As per the rules followed in the above steps, find out in each of the following questions the appropriate steps for the given input. Input for the questions: Input: for 52 all 96 25jam road 15 hut73 bus stop 38 46 (All the numbers given in the arrangement are two-digit numbers.) Which of the following would be step VII?

  1. A.stop road jam hut for bus all 15 96 73 5246 38 25
  2. Broad jam hut for bus all stop 15 25 38 46 52 73 96
  3. Cstop road jam hut for bus all 96 73 5246 38 25 15Correct
  4. D. jam hut for bus all 25 road stop 15 96 73 52 46 38
  5. EThere will be no such step.

Answer: C. stop road jam hut for bus all 96 73 5246 38 25 15

Official answer key verified. Detailed explanation coming soon.

Source: IBPS Common Written Exam PO/MT September 2011 (exampapers247 PDF compilation) · reliable-secondary

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