ibps-csa 2014 · Question 4 of 196
Alphanumeric Series
Here, there is a peculiar pattern followed. The initial element of the series is first written. Then alternate element in the series is written. Again next alternative element is written. After leaving one element, same process is repeated for the second term. Then, Third term is formed by leaving two elements. We are supposed to find 4th term. So, Leaving 3 elements J & K will be formed. Hence, the group formed is J&K.
Source: IBPS Clerk CWE paper held 14-12-2014 — solved-paper book excerpt (CollegeDunia) with publisher answer key; sections cross-verified against BankingAdda / FreshersNow / CollegeDekho 14-12-2014 papers · memory-based
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