BPSC (Bihar PCS) 2025 · Question 70 of 145
General Science
1 unit of electricity = 1 kilowatt-hour (kWh) 1 kWh = 1000 watt × 3600 seconds = 3.6 × 10⁶ joules Energy consumed = 250 units = 250 × 3.6 × 10⁶ J = 9.0 × 10⁸ J So, the total energy = 9 × 10⁸ joules. Therefore, option (C) is the correct answer.
Source: 71st BPSC CCE Prelims 2025 (Set H)
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