BPSC (Bihar PCS) 2025 · Question 129 of 145
Miscellaneous
Let S= Seema’s present age, R= Rahul present age and L= Laxmi present age R+ 4 = 31 years, R= 27 years Rahul is three times Seema= 9 Laxmi was twice as old as Rahul four years ago = (L-4)= 2×(R-4) (L-4) = 23 × 2 = 46 +4 = 50 Therefore, option (D) is the correct answer.
Source: 71st BPSC CCE Prelims 2025 (Set H)
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