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  9. Q171

APSC CCE 2024 · Question 171 of 178

What combination of alphanumeric characters should occupy the vacant space of the given table? Row1: 1Y, 4Z, 7X Row2: 10Z, ?, 50Y Row3: 3Z, 2Y, 1X

Logical Reasoning

  1. A25X
  2. B20XCorrect
  3. C1X
  4. D1Z

Answer: B. 20X

Explanation

In each column, middle number = (top)^2 + (bottom)^2 (1+9=10, 16+4=20, 49+1=50); the letter X completes the X/Y/Z set in row 2; official key gives (B).

Source: APSC CCE Prelims 2024 GS Paper-II, official Series-A paper (DUCN-II-24/44-A), answer from official Series-A key

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