APSC CCE 2022 · Question 146 of 176
Basic Numeracy
For each of the 8 sides, the third vertex must avoid the 2 adjacent vertices and the 2 vertices whose joining lines pass through the centre, leaving 2 valid vertices per side: 8 × 2 = 16 triangles.
Source: APSC CCE Prelims 2022 GS Paper-II, official Series-D key
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